Friday, October 18, 2019

Enviromental Assignment Example | Topics and Well Written Essays - 500 words

Enviromental - Assignment Example Mass of Ozone in troposphere = 2.28Ãâ€"1013g. Similarly, it means 3 ppm = 3 volumes of Ozone gas/106 volumes of air. Ppmv of Ozone in stratosphere = (ppm/MW) Ãâ€" 22.4. Therefore, ppmv = (3/48) Ãâ€" 22.4 = 1.4ppmv. This means that 1 million volumes of air have 1.4 volumes of Ozone by mass. 1 million volumes of air in stratosphere represent 2.5Ãâ€"1020 g of air. What about 1.4 ppmv of Ozone? Mass of Ozone = (1.4Ãâ€" 2.5Ãâ€"1020)/1Ãâ€"106. Mass of Ozone = 3.5Ãâ€"1014g. Partial pressure, Px = CxÃâ€"P where Px is partial pressure, Cx is the partial concentration of gas x and P is the entire pressure. N2O, MW of 44, has a concentration of 0.31ppm at ground level. Ne, MW of 20, has concentration of 18 ppm at 30km. Pressure of Ne with respect to the altitude of 30 km is given by Pa = 0.9877a, where a = altitude in 100’s of meters. Therefore, Pa = 0.9877300= 0.0244atm. Partial pressure of Ne = 18ppmÃâ€"0.0244 = 0.44 atm. Partial pressure of N2O = 0.31Ãâ€"1 = 0.31 atm. Therefore, Ne has a greater partial pressure that N2O. 100% relative humidity represents 0.031atm H2O. On the other hand, liquid water is present at 100ug/m3. Assuming a temperature of 25oC, then we will convert ug/m3 into ppmv using the formula ppmv = (mg/m3 Ãâ€" oK)/ (0.08205 Ãâ€" MW). With respect to water vapor, ppmv = (0.1 mg/m3 Ãâ€" 298)/(0.08205 Ãâ€" 18). Ppmv = 20.18. Using PV = nRT, then moles of air in 1 mol of gaseous mixture = 1Ãâ€"106 / 6.023Ãâ€"1023 = 1.66Ãâ€"10-18. Converting moles into volume we get 4.06Ãâ€"10-14 cm3. Therefore, the urban atmosphere contains 20.18 molecules of liquid H2O /4.06Ãâ€"10-14 cm3 of air. On water vapor, 30% relative humidity represents (30 Ãâ€" 0.031)/ 100 = 0.0093 atm. In 1 atm, volume of gas = 24.45L, in 0.0093 atm, volume of vapor = (0.0093 Ãâ€" 24.45)/1 = 0.227L. Based on theory, 1 mol = 24.45L (Dr Richards 01). Therefore, 0.227L contains (0.227Ãâ€"1)/24.45 = 0.0093 molecules/L. In terms of cm3, the atmosphere has 9.3

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